Solving Quadratic (2nd degree) Equations
There are 3 widely used methods for solving quadratic equations. A quadratic (or second-degree) equation is an equation in which the variable has an exponent of 2.
The standard form of a quadratic equation is
.
The standard form of a quadratic equation is
The three methods used to solve quadratic equations are: 1) factoring, 2) the square root property, and 3) the quadratic formula. Quadratic equations generally have 2 solutions.
1) Factoring is one method used to solve second-degree and larger equations. First the equation must be written in standard form. This means that the polynomial must be in descending form and set equal to zero. Next, you must factor the polynomial. (You may want to review factoring.) Once the polynomial is factored, set any factor which contains a variable equal to zero and solve (using isolation) for the variable. Check your answer in the original equation. Every quadratic equation has two solutions, although in the case of a perfect square trinomial both of the solutions are the same.
If the equation is factored and set equal to zero as in the example,
, then
and
.
Solve the equation,
. First, you must get the equation in standard form.
This means that you must add 16 to both sides so that the –16 is removed from the left side of the equation and the equation will then be equal to zero …
…
. Now you are ready to factor,
. Set the factors equal to zero. Since
is repeated twice as a factor, there are two solutions, but they are both the same. Thus,
is the only “unique” solution to this problem. This is a perfect square trinomial, which factored into the square of a binomial.
If the problem has a degree of three (in other words the variable in the equation is cubed) then you will find three solutions. Example:
.
First, factor the GCF of +2x from each of the terms of the polynomial …
.
Next factor,
. We now have three factors which contain variables, therefore,
and
and
. This example of a third degree equation has three solutions
.
If the equation is factored and set equal to zero as in the example,
Solve the equation,
This means that you must add 16 to both sides so that the –16 is removed from the left side of the equation and the equation will then be equal to zero …
If the problem has a degree of three (in other words the variable in the equation is cubed) then you will find three solutions. Example:
First, factor the GCF of +2x from each of the terms of the polynomial …
Next factor,
2) The square root property involves taking the square roots of both sides of an equation. Before taking the square root of each side, you must isolate the term that contains the squared variable. Once this squared-variable term is fully isolated, you will take the square root of both sides and solve for the variable. We now introduce the possibility of two roots for every square root, one positive and one negative. Place a
sign in front of the side containing the constant before you take the square root of that side.
Example 1:
each side
negative root
solved this equation
Example 2:
square root of each side
rational numbers, which means …
Example 3:
beginning
variable
right-hand side, these numbers may not be combined since
–1 is a rational number and
In each of the first 3 examples involving the square root property, notice that there were no first-degree terms. These equations although they are quadratic in nature, have the form
. To solve a quadratic equation that contains a first-degree term using the square root property would involve completing the square which is another "trick" that will be explained in another lesson.
3) The third method for solving quadratic equations described uses the quadratic formula ó Bhaskara's Formula
This formula is
. If you notice, the right hand side has variables a, b, and c.
These variables are the coefficients of the terms of the quadratic equation. (Remember the standard form is
.)
This formula is
These variables are the coefficients of the terms of the quadratic equation. (Remember the standard form is
Example 4:
…move terms to one side
RESPONDE:
Skimming:
1) ¿Cuál es el tema principal del texto?
2) ¿Cuál es la forma estándar o general de una ecuación de segundo grado?
Scanning:
3) Según el texto ¿Cuántos métodos hay para resolver ecuaciones de segundo grado?
4) Generalmente, ¿cuántas soluciones tiene una ecuación de segundo grado?
Reading in detail:
5) Utilizando la fórmula de Bhaskara resuelve: x2-x-2=0
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